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49q^2-25=0
a = 49; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·49·(-25)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70}{2*49}=\frac{-70}{98} =-5/7 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70}{2*49}=\frac{70}{98} =5/7 $
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